8+20x=980x^2

Solution for 8+20x=980x^2 equation:

8+20x=980x^2

We move all terms to the left:

8+20x-(980x^2)=0

determiningTheFunctionDomain
-980x^2+20x+8=0

a = -980; b = 20; c = +8;
Δ = b2-4ac
Δ = 202-4·(-980)·8
Δ = 31760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{31760}=\sqrt{16*1985}=\sqrt{16}*\sqrt{1985}=4\sqrt{1985}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{1985}}{2*-980}=\frac{-20-4\sqrt{1985}}{-1960}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{1985}}{2*-980}=\frac{-20+4\sqrt{1985}}{-1960}
$